Factor by Grouping 3y^3-2y^2-9y+6

$3 y^{3} - 2 y^{2} - 9 y + 6$

Step 1

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(3 y^{3} - 2 y^{2}) - 9 y + 6$

Factor out the greatest common factor (GCF) from each group.

$y^{2} (3 y - 2) - 3 (3 y - 2)$

Step 2

Factor the polynomial by factoring out the greatest common factor, $3 y - 2$ .

$(3 y - 2) (y^{2} - 3)$