Factor by Grouping y^2+yt-12t^2

$y^{2} + y t - 12 t^{2}$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = - 12 \cdot 1 = - 12$ and whose sum is $b = 1$ .

Reorder terms.

$- 12 t^{2} + y^{2} + t y$

Reorder $y^{2}$ and $t y$ .

$- 12 t^{2} + t y + y^{2}$

Factor $1$ out of $t y$ .

$- 12 t^{2} + 1 (t y) + y^{2}$

Rewrite $1$ as $- 3$ plus $4$

$- 12 t^{2} + (- 3 + 4) (t y) + y^{2}$

Apply the distributive property.

$- 12 t^{2} - 3 (t y) + 4 (t y) + y^{2}$

Remove unnecessary parentheses.

$- 12 t^{2} - 3 t y + 4 (t y) + y^{2}$

Remove unnecessary parentheses.

$- 12 t^{2} - 3 t y + 4 t y + y^{2}$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(- 12 t^{2} - 3 t y) + 4 t y + y^{2}$

Factor out the greatest common factor (GCF) from each group.

$3 t (- 4 t - y) - y (- 4 t - y)$

Step 3

Factor the polynomial by factoring out the greatest common factor, $- 4 t - y$ .

$(- 4 t - y) (3 t - y)$

Factor by Grouping y^2+yt-12t^2

Related Questions

Support LCMGCF.com by disabling your adblocker.