Factor d^2-20d+100

$d^{2} - 20 d + 100$

Step 1

Rewrite $100$ as $10^{2}$ .

$d^{2} - 20 d + 10^{2}$

Step 2

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$20 d = 2 \cdot d \cdot 10$

Step 3

Rewrite the polynomial.

$d^{2} - 2 \cdot d \cdot 10 + 10^{2}$

Step 4

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = d$ and $b = 10$ .

${(d - 10)}^{2}$