Factor F(x)=x^2-25

$F (x) = x^{2} - 25$

Step 1

Rewrite $25$ as $5^{2}$ .

$F (x) = x^{2} - 5^{2}$

Step 2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 5$ .

$F (x) = (x + 5) (x - 5)$