Factor g^2-28g+196

$g^{2} - 28 g + 196$

Step 1

Rewrite $196$ as $14^{2}$ .

$g^{2} - 28 g + 14^{2}$

Step 2

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$28 g = 2 \cdot g \cdot 14$

Step 3

Rewrite the polynomial.

$g^{2} - 2 \cdot g \cdot 14 + 14^{2}$

Step 4

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = g$ and $b = 14$ .

${(g - 14)}^{2}$