Factor s^3+125

$s^{3} + 125$

Step 1

Rewrite $125$ as $5^{3}$ .

$s^{3} + 5^{3}$

Step 2

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = s$ and $b = 5$ .

$(s + 5) (s^{2} - s \cdot 5 + 5^{2})$

Step 3

Simplify.

Multiply $5$ by $- 1$ .

$(s + 5) (s^{2} - 5 s + 5^{2})$

Raise $5$ to the power of $2$ .

$(s + 5) (s^{2} - 5 s + 25)$

Factor s^3+125

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