Factor t^3-27

$t^{3} - 27$

Step 1

Rewrite $27$ as $3^{3}$ .

$t^{3} - 3^{3}$

Step 2

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = t$ and $b = 3$ .

$(t - 3) (t^{2} + t \cdot 3 + 3^{2})$

Step 3

Simplify.

Move $3$ to the left of $t$ .

$(t - 3) (t^{2} + 3 t + 3^{2})$

Raise $3$ to the power of $2$ .

$(t - 3) (t^{2} + 3 t + 9)$

Factor t^3-27

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