Factor v^3-64

$v^{3} - 64$

Step 1

Rewrite $64$ as $4^{3}$ .

$v^{3} - 4^{3}$

Step 2

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = v$ and $b = 4$ .

$(v - 4) (v^{2} + v \cdot 4 + 4^{2})$

Step 3

Simplify.

Move $4$ to the left of $v$ .

$(v - 4) (v^{2} + 4 v + 4^{2})$

Raise $4$ to the power of $2$ .

$(v - 4) (v^{2} + 4 v + 16)$

Factor v^3-64

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