Factor x^2-11x+19=-5

$x^{2} - 11 x + 19 = - 5$

Add $5$ to both sides of the equation.

$x^{2} - 11 x + 19 + 5 = 0$

Add $19$ and $5$ .

$x^{2} - 11 x + 24 = 0$

Factor $x^{2} - 11 x + 24$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $24$ and whose sum is $- 11$ .

$- 8, - 3$

Write the factored form using these integers.

$(x - 8) (x - 3) = 0$

Factor x^2-11x+19=-5

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