Factor x^2-16xy+64y^2

$x^{2} - 16 x y + 64 y^{2}$

Step 1

Rewrite $64 y^{2}$ as ${(8 y)}^{2}$ .

$x^{2} - 16 x y + {(8 y)}^{2}$

Step 2

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$16 x y = 2 \cdot x \cdot (8 y)$

Step 3

Rewrite the polynomial.

$x^{2} - 2 \cdot x \cdot (8 y) + {(8 y)}^{2}$

Step 4

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = x$ and $b = 8 y$ .

${(x - 8 y)}^{2}$