Factor x^2-20=x

$x^{2} - 20 = x$

Step 1

Subtract $x$ from both sides of the equation.

$x^{2} - 20 - x = 0$

Step 2

Factor $x^{2} - 20 - x$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 20$ and whose sum is $- 1$ .

$- 5, 4$

Write the factored form using these integers.

$(x - 5) (x + 4) = 0$

Factor x^2-20=x

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