Factor x^2-4/9

$x^{2} - \frac{4}{9}$

Step 1

Rewrite $\frac{4}{9}$ as ${(\frac{2}{3})}^{2}$ .

$x^{2} - {(\frac{2}{3})}^{2}$

Step 2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = \frac{2}{3}$ .

$(x + \frac{2}{3}) (x - \frac{2}{3})$

Factor x^2-4/9

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