Factor x^3-4x^2+3x

$x^{3} - 4 x^{2} + 3 x$

Step 1

Factor $x$ out of $x^{3} - 4 x^{2} + 3 x$ .

Factor $x$ out of $x^{3}$ .

$x \cdot x^{2} - 4 x^{2} + 3 x$

Factor $x$ out of $- 4 x^{2}$ .

$x \cdot x^{2} + x (- 4 x) + 3 x$

Factor $x$ out of $3 x$ .

$x \cdot x^{2} + x (- 4 x) + x \cdot 3$

Factor $x$ out of $x \cdot x^{2} + x (- 4 x)$ .

$x (x^{2} - 4 x) + x \cdot 3$

Factor $x$ out of $x (x^{2} - 4 x) + x \cdot 3$ .

$x (x^{2} - 4 x + 3)$

Step 2

Factor.

Factor $x^{2} - 4 x + 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $3$ and whose sum is $- 4$ .

$- 3, - 1$

Write the factored form using these integers.

$x ((x - 3) (x - 1))$

Remove unnecessary parentheses.

$x (x - 3) (x - 1)$

Factor x^3-4x^2+3x

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