Factor x^3+x^2-4x-4=0

$x^{3} + x^{2} - 4 x - 4 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(x^{3} + x^{2}) - 4 x - 4 = 0$

Factor out the greatest common factor (GCF) from each group.

$x^{2} (x + 1) - 4 (x + 1) = 0$

Factor the polynomial by factoring out the greatest common factor, $x + 1$ .

$(x + 1) (x^{2} - 4) = 0$

Rewrite $4$ as $2^{2}$ .

$(x + 1) (x^{2} - 2^{2}) = 0$

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$(x + 1) ((x + 2) (x - 2)) = 0$

Remove unnecessary parentheses.

$(x + 1) (x + 2) (x - 2) = 0$