Factor (x-y)^2-4z^2

${(x - y)}^{2} - 4 z^{2}$

Rewrite $4 z^{2}$ as ${(2 z)}^{2}$ .

${(x - y)}^{2} - {(2 z)}^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x - y$ and $b = 2 z$ .

$(x - y + 2 z) (x - y - (2 z))$

Multiply $2$ by $- 1$ .

$(x - y + 2 z) (x - y - 2 z)$

Factor (x-y)^2-4z^2

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