Factor y^2-16y+64

$y^{2} - 16 y + 64$

Step 1

Rewrite $64$ as $8^{2}$ .

$y^{2} - 16 y + 8^{2}$

Step 2

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$16 y = 2 \cdot y \cdot 8$

Step 3

Rewrite the polynomial.

$y^{2} - 2 \cdot y \cdot 8 + 8^{2}$

Step 4

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = y$ and $b = 8$ .

${(y - 8)}^{2}$