Factor y^3+1

$y^{3} + 1$

Step 1

Rewrite $1$ as $1^{3}$ .

$y^{3} + 1^{3}$

Step 2

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = y$ and $b = 1$ .

$(y + 1) (y^{2} - y \cdot 1 + 1^{2})$

Step 3

Simplify.

Multiply $- 1$ by $1$ .

$(y + 1) (y^{2} - y + 1^{2})$

One to any power is one.

$(y + 1) (y^{2} - y + 1)$

Factor y^3+1

Related Questions

Support LCMGCF.com by disabling your adblocker.