Find a,b,c 0=1/2x^2-3x-2

$0 = \frac{1}{2} x^{2} - 3 x - 2$

Step 1

Move all terms to the left side of the equation and simplify.

Simplify the right side.

Combine $\frac{1}{2}$ and $x^{2}$ .

$0 = \frac{x^{2}}{2} - 3 x - 2$

Move all the expressions to the left side of the equation.

Subtract $\frac{x^{2}}{2}$ from both sides of the equation.

$- \frac{x^{2}}{2} = - 3 x - 2$

Add $3 x$ to both sides of the equation.

$- \frac{x^{2}}{2} + 3 x = - 2$

Add $2$ to both sides of the equation.

$- \frac{x^{2}}{2} + 3 x + 2 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - \frac{1}{2}$ , $b = 3$ , $c = 2$