Find a,b,c 0.3x^2+5x-7=0

$0.3 x^{2} + 5 x - 7 = 0$

Step 1

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 2

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 0.3$ , $b = 5$ , $c = - 7$