Find a,b,c 0=4x^2+12x+9

$0 = 4 x^{2} + 12 x + 9$

Step 1

Move all the expressions to the left side of the equation.

Subtract $4 x^{2}$ from both sides of the equation.

$- 4 x^{2} = 12 x + 9$

Subtract $12 x$ from both sides of the equation.

$- 4 x^{2} - 12 x = 9$

Subtract $9$ from both sides of the equation.

$- 4 x^{2} - 12 x - 9 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - 4$ , $b = - 12$ , $c = - 9$