Find a,b,c 0=5x-4x^2-2

$0 = 5 x - 4 x^{2} - 2$

Step 1

Move all the expressions to the left side of the equation.

Subtract $5 x$ from both sides of the equation.

$- 5 x = - 4 x^{2} - 2$

Add $4 x^{2}$ to both sides of the equation.

$- 5 x + 4 x^{2} = - 2$

Add $2$ to both sides of the equation.

$- 5 x + 4 x^{2} + 2 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 4$ , $b = - 5$ , $c = 2$