Find a,b,c 12x^2+13x-6=0

$12 x^{2} + 13 x - 6 = 0$

Step 1

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 2

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 12$ , $b = 13$ , $c = - 6$