Find a,b,c 2x^2-4x=6

$2 x^{2} - 4 x = 6$

Step 1

Subtract $6$ from both sides of the equation.

$2 x^{2} - 4 x - 6 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 2$ , $b = - 4$ , $c = - 6$