Find a,b,c 2y^2-3y+5=0

$2 y^{2} - 3 y + 5 = 0$

Step 1

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a y^{2} + b y + c$

Step 2

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 2$ , $b = - 3$ , $c = 5$