Find a,b,c 3x+2x^2=5x^2-6

$3 x + 2 x^{2} = 5 x^{2} - 6$

Step 1

Move all terms to the left side of the equation and simplify.

Move all the expressions to the left side of the equation.

Subtract $5 x^{2}$ from both sides of the equation.

$3 x + 2 x^{2} - 5 x^{2} = - 6$

Add $6$ to both sides of the equation.

$3 x + 2 x^{2} - 5 x^{2} + 6 = 0$

Subtract $5 x^{2}$ from $2 x^{2}$ .

$3 x - 3 x^{2} + 6 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - 3$ , $b = 3$ , $c = 6$