Find a,b,c 4x^2=-15

$4 x^{2} = - 15$

Step 1

Add $15$ to both sides of the equation.

$4 x^{2} + 15 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 4$ , $b = 0$ , $c = 15$