Find a,b,c -4x^2=8x-3

$- 4 x^{2} = 8 x - 3$

Step 1

Move all the expressions to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$- 4 x^{2} - 8 x = - 3$

Add $3$ to both sides of the equation.

$- 4 x^{2} - 8 x + 3 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - 4$ , $b = - 8$ , $c = 3$