Find a,b,c 4y^2-5y=3

$4 y^{2} - 5 y = 3$

Step 1

Subtract $3$ from both sides of the equation.

$4 y^{2} - 5 y - 3 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a y^{2} + b y + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 4$ , $b = - 5$ , $c = - 3$