Find a,b,c 5x^2-6x=8

$5 x^{2} - 6 x = 8$

Subtract $8$ from both sides of the equation.

$5 x^{2} - 6 x - 8 = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 5$ , $b = - 6$ , $c = - 8$