Find a,b,c 6x^2-3x=2x+1

$6 x^{2} - 3 x = 2 x + 1$

Step 1

Move all terms to the left side of the equation and simplify.

Move all the expressions to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$6 x^{2} - 3 x - 2 x = 1$

Subtract $1$ from both sides of the equation.

$6 x^{2} - 3 x - 2 x - 1 = 0$

Subtract $2 x$ from $- 3 x$ .

$6 x^{2} - 5 x - 1 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 6$ , $b = - 5$ , $c = - 1$