Find a,b,c 6x^2-5x-3=0

$6 x^{2} - 5 x - 3 = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 6$ , $b = - 5$ , $c = - 3$