Find a,b,c 6x^2+8=x

$6 x^{2} + 8 = x$

Step 1

Subtract $x$ from both sides of the equation.

$6 x^{2} + 8 - x = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 6$ , $b = - 1$ , $c = 8$