Find a,b,c 7(2e-1)-3=6+6e

$7 (2 e - 1) - 3 = 6 + 6 e$

Step 1

Move all terms to the left side of the equation and simplify.

Simplify the left side.

Simplify $7 (2 e - 1) - 3$ .

Simplify each term.

Apply the distributive property.

$7 (2 e) + 7 \cdot - 1 - 3 = 6 + 6 e$

Multiply $2$ by $7$ .

$14 e + 7 \cdot - 1 - 3 = 6 + 6 e$

Multiply $7$ by $- 1$ .

$14 e - 7 - 3 = 6 + 6 e$

Subtract $3$ from $- 7$ .

$14 e - 10 = 6 + 6 e$

Move all the expressions to the left side of the equation.

Subtract $6$ from both sides of the equation.

$14 e - 10 - 6 = 6 e$

Subtract $6 e$ from both sides of the equation.

$14 e - 10 - 6 - 6 e = 0$

Simplify $14 e - 10 - 6 - 6 e$ .

Subtract $6 e$ from $14 e$ .

$8 e - 10 - 6 = 0$

Subtract $6$ from $- 10$ .

$8 e - 16 = 0$

Step 2

Simplify $8 (2.71828182) - 16$ .

Multiply $8$ by $2.71828182$ .

$21.74625462 - 16 = 0$

Subtract $16$ from $21.74625462$ .

$5.74625462 = 0$

Step 3

Since $5.74625462 \neq 0$ , there are no solutions.

No solution