Find a,b,c 8=12x-3x^2

$8 = 12 x - 3 x^{2}$

Step 1

Move all the expressions to the left side of the equation.

Subtract $12 x$ from both sides of the equation.

$8 - 12 x = - 3 x^{2}$

Add $3 x^{2}$ to both sides of the equation.

$8 - 12 x + 3 x^{2} = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 3$ , $b = - 12$ , $c = 8$