Find a,b,c 8x^2=15-3x

$8 x^{2} = 15 - 3 x$

Move all the expressions to the left side of the equation.

Subtract $15$ from both sides of the equation.

$8 x^{2} - 15 = - 3 x$

Add $3 x$ to both sides of the equation.

$8 x^{2} - 15 + 3 x = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 8$ , $b = 3$ , $c = - 15$