Find a,b,c -9x=13-5x^2

$- 9 x = 13 - 5 x^{2}$

Step 1

Move all the expressions to the left side of the equation.

Subtract $13$ from both sides of the equation.

$- 9 x - 13 = - 5 x^{2}$

Add $5 x^{2}$ to both sides of the equation.

$- 9 x - 13 + 5 x^{2} = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 5$ , $b = - 9$ , $c = - 13$