Find a,b,c 9x^2-3x=18

$9 x^{2} - 3 x = 18$

Step 1

Subtract $18$ from both sides of the equation.

$9 x^{2} - 3 x - 18 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 9$ , $b = - 3$ , $c = - 18$