Find a,b,c -9x^2=6x+1

$- 9 x^{2} = 6 x + 1$

Step 1

Move all the expressions to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$- 9 x^{2} - 6 x = 1$

Subtract $1$ from both sides of the equation.

$- 9 x^{2} - 6 x - 1 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - 9$ , $b = - 6$ , $c = - 1$