Find a,b,c -x^2-12x-36=0

$- x^{2} - 12 x - 36 = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - 1$ , $b = - 12$ , $c = - 36$