Find a,b,c x^2=14x-49

$x^{2} = 14 x - 49$

Step 1

Move all the expressions to the left side of the equation.

Subtract $14 x$ from both sides of the equation.

$x^{2} - 14 x = - 49$

Add $49$ to both sides of the equation.

$x^{2} - 14 x + 49 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 1$ , $b = - 14$ , $c = 49$