Find a,b,c x^2+2x+1=5x+6

$x^{2} + 2 x + 1 = 5 x + 6$

Move all terms to the left side of the equation and simplify.

Move all the expressions to the left side of the equation.

Subtract $5 x$ from both sides of the equation.

$x^{2} + 2 x + 1 - 5 x = 6$

Subtract $6$ from both sides of the equation.

$x^{2} + 2 x + 1 - 5 x - 6 = 0$

Simplify $x^{2} + 2 x + 1 - 5 x - 6$ .

Subtract $5 x$ from $2 x$ .

$x^{2} - 3 x + 1 - 6 = 0$

Subtract $6$ from $1$ .

$x^{2} - 3 x - 5 = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 1$ , $b = - 3$ , $c = - 5$