Find a,b,c x^2+4x+10=3

$x^{2} + 4 x + 10 = 3$

Move all terms to the left side of the equation and simplify.

Subtract $3$ from both sides of the equation.

$x^{2} + 4 x + 10 - 3 = 0$

Subtract $3$ from $10$ .

$x^{2} + 4 x + 7 = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 1$ , $b = 4$ , $c = 7$