Find a,b,c x^2=7x+1

$x^{2} = 7 x + 1$

Move all the expressions to the left side of the equation.

Subtract $7 x$ from both sides of the equation.

$x^{2} - 7 x = 1$

Subtract $1$ from both sides of the equation.

$x^{2} - 7 x - 1 = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 1$ , $b = - 7$ , $c = - 1$