Find a,b,c y^2-24y+144=0

$y^{2} - 24 y + 144 = 0$

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a y^{2} + b y + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 1$ , $b = - 24$ , $c = 144$