Find All Complex Solutions 3(x+10)+6=3(x+12)

$3 (x + 10) + 6 = 3 (x + 12)$

Step 1

Simplify $3 (x + 10) + 6$ .

Simplify each term.

Apply the distributive property.

$3 x + 3 \cdot 10 + 6 = 3 (x + 12)$

Multiply $3$ by $10$ .

$3 x + 30 + 6 = 3 (x + 12)$

Add $30$ and $6$ .

$3 x + 36 = 3 (x + 12)$

Step 2

Simplify $3 (x + 12)$ .

Apply the distributive property.

$3 x + 36 = 3 x + 3 \cdot 12$

Multiply $3$ by $12$ .

$3 x + 36 = 3 x + 36$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$3 x + 36 - 3 x = 36$

Combine the opposite terms in $3 x + 36 - 3 x$ .

Subtract $3 x$ from $3 x$ .

$0 + 36 = 36$

Add $0$ and $36$ .

$36 = 36$

Step 4

Since $36 = 36$ , the equation will always be true.

Always true