Find All Complex Solutions -4(x+1)+6x=2(x+2)-8

$- 4 (x + 1) + 6 x = 2 (x + 2) - 8$

Simplify $- 4 (x + 1) + 6 x$ .

Simplify each term.

Apply the distributive property.

$- 4 x - 4 \cdot 1 + 6 x = 2 (x + 2) - 8$

Multiply $- 4$ by $1$ .

$- 4 x - 4 + 6 x = 2 (x + 2) - 8$

Add $- 4 x$ and $6 x$ .

$2 x - 4 = 2 (x + 2) - 8$

Simplify $2 (x + 2) - 8$ .

Simplify each term.

Apply the distributive property.

$2 x - 4 = 2 x + 2 \cdot 2 - 8$

Multiply $2$ by $2$ .

$2 x - 4 = 2 x + 4 - 8$

Subtract $8$ from $4$ .

$2 x - 4 = 2 x - 4$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$2 x - 4 - 2 x = - 4$

Combine the opposite terms in $2 x - 4 - 2 x$ .

Subtract $2 x$ from $2 x$ .

$0 - 4 = - 4$

Subtract $4$ from $0$ .

$- 4 = - 4$

Since $- 4 = - 4$ , the equation will always be true.

Always true