Find All Complex Solutions -4(x-5)+8x=9x-3

$- 4 (x - 5) + 8 x = 9 x - 3$

Simplify $- 4 (x - 5) + 8 x$ .

Simplify each term.

Apply the distributive property.

$- 4 x - 4 \cdot - 5 + 8 x = 9 x - 3$

Multiply $- 4$ by $- 5$ .

$- 4 x + 20 + 8 x = 9 x - 3$

Add $- 4 x$ and $8 x$ .

$4 x + 20 = 9 x - 3$

Move all terms containing $x$ to the left side of the equation.

Subtract $9 x$ from both sides of the equation.

$4 x + 20 - 9 x = - 3$

Subtract $9 x$ from $4 x$ .

$- 5 x + 20 = - 3$

Move all terms not containing $x$ to the right side of the equation.

Subtract $20$ from both sides of the equation.

$- 5 x = - 3 - 20$

Subtract $20$ from $- 3$ .

$- 5 x = - 23$

Divide each term in $- 5 x = - 23$ by $- 5$ and simplify.

Divide each term in $- 5 x = - 23$ by $- 5$ .

$\frac{- 5 x}{- 5} = \frac{- 23}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 x}{- 5} = \frac{- 23}{- 5}$

Divide $x$ by $1$ .

$x = \frac{- 23}{- 5}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{23}{5}$