Find All Complex Solutions x^2-16x+145=0

$x^{2} - 16 x + 145 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 1$ , $b = - 16$ , and $c = 145$ into the quadratic formula and solve for $x$ .

$\frac{16 \pm \sqrt{{(- 16)}^{2} - 4 \cdot (1 \cdot 145)}}{2 \cdot 1}$

Step 3

Simplify.

Simplify the numerator.

Raise $- 16$ to the power of $2$ .

$x = \frac{16 \pm \sqrt{256 - 4 \cdot 1 \cdot 145}}{2 \cdot 1}$

Multiply $- 4 \cdot 1 \cdot 145$ .

Multiply $- 4$ by $1$ .

$x = \frac{16 \pm \sqrt{256 - 4 \cdot 145}}{2 \cdot 1}$

Multiply $- 4$ by $145$ .

$x = \frac{16 \pm \sqrt{256 - 580}}{2 \cdot 1}$

Subtract $580$ from $256$ .

$x = \frac{16 \pm \sqrt{- 324}}{2 \cdot 1}$

Rewrite $- 324$ as $- 1 (324)$ .

$x = \frac{16 \pm \sqrt{- 1 \cdot 324}}{2 \cdot 1}$

Rewrite $\sqrt{- 1 (324)}$ as $\sqrt{- 1} \cdot \sqrt{324}$ .

$x = \frac{16 \pm \sqrt{- 1} \cdot \sqrt{324}}{2 \cdot 1}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{16 \pm i \cdot \sqrt{324}}{2 \cdot 1}$

Rewrite $324$ as $18^{2}$ .

$x = \frac{16 \pm i \cdot \sqrt{18^{2}}}{2 \cdot 1}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{16 \pm i \cdot 18}{2 \cdot 1}$

Move $18$ to the left of $i$ .

$x = \frac{16 \pm 18 i}{2 \cdot 1}$

Multiply $2$ by $1$ .

$x = \frac{16 \pm 18 i}{2}$

Simplify $\frac{16 \pm 18 i}{2}$ .

$x = 8 \pm 9 i$