Find Any Equation Parallel to the Line x+2y=5

$x + 2 y = 5$

Choose a point that the parallel line will pass through.

$(0, 0)$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $x$ from both sides of the equation.

$2 y = 5 - x$

Divide each term in $2 y = 5 - x$ by $2$ and simplify.

Divide each term in $2 y = 5 - x$ by $2$ .

$\frac{2 y}{2} = \frac{5}{2} + \frac{- x}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{5}{2} + \frac{- x}{2}$

Divide $y$ by $1$ .

$y = \frac{5}{2} + \frac{- x}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$y = \frac{5}{2} - \frac{x}{2}$

Write in $y = m x + b$ form.

Reorder $\frac{5}{2}$ and $- \frac{x}{2}$ .

$y = - \frac{x}{2} + \frac{5}{2}$

Reorder terms.

$y = - (\frac{1}{2} x) + \frac{5}{2}$

Remove parentheses.

$y = - \frac{1}{2} x + \frac{5}{2}$

Using the slope-intercept form, the slope is $- \frac{1}{2}$ .

$m = - \frac{1}{2}$

To find an equation that is parallel, the slopes must be equal. Find the parallel line using the point-slope formula.

Use the slope $- \frac{1}{2}$ and a given point $(0, 0)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (0) = - \frac{1}{2} \cdot (x - (0))$

Simplify the equation and keep it in point-slope form.

$y + 0 = - \frac{1}{2} \cdot (x + 0)$

Solve for $y$ .

Add $y$ and $0$ .

$y = - \frac{1}{2} \cdot (x + 0)$

Simplify $- \frac{1}{2} \cdot (x + 0)$ .

Add $x$ and $0$ .

$y = - \frac{1}{2} \cdot x$

Combine $x$ and $\frac{1}{2}$ .

$y = - \frac{x}{2}$

Write in $y = m x + b$ form.

Reorder terms.

$y = - (\frac{1}{2} x)$

Remove parentheses.

$y = - \frac{1}{2} x$

Find Any Equation Parallel to the Line x+2y=5

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