Find Any Equation Perpendicular to the Line 2x+3y=-17

$2 x + 3 y = - 17$

Step 1

Choose a point that the perpendicular line will pass through.

$(0, 0)$

Step 2

Solve $2 x + 3 y = - 17$ .

Subtract $2 x$ from both sides of the equation.

$3 y = - 17 - 2 x$

Divide each term in $3 y = - 17 - 2 x$ by $3$ and simplify.

Divide each term in $3 y = - 17 - 2 x$ by $3$ .

$\frac{3 y}{3} = \frac{- 17}{3} + \frac{- 2 x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 17}{3} + \frac{- 2 x}{3}$

Divide $y$ by $1$ .

$y = \frac{- 17}{3} + \frac{- 2 x}{3}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{17}{3} + \frac{- 2 x}{3}$

Move the negative in front of the fraction.

$y = - \frac{17}{3} - \frac{2 x}{3}$

Step 3

Find the slope when $y = - \frac{17}{3} - \frac{2 x}{3}$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- \frac{17}{3}$ and $- \frac{2 x}{3}$ .

$y = - \frac{2 x}{3} - \frac{17}{3}$

Write in $y = m x + b$ form.

Reorder terms.

$y = - (\frac{2}{3} x) - \frac{17}{3}$

Remove parentheses.

$y = - \frac{2}{3} x - \frac{17}{3}$

Using the slope-intercept form, the slope is $- \frac{2}{3}$ .

$m = - \frac{2}{3}$

Step 4

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- \frac{2}{3}}$

Step 5

Simplify $- \frac{1}{- \frac{2}{3}}$ to find the slope of the perpendicular line.

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$m_{perpendicular} = - \frac{- 1 \cdot - 1}{- \frac{2}{3}}$

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{\frac{2}{3}}$

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = 1 (\frac{3}{2})$

Multiply $\frac{3}{2}$ by $1$ .

$m_{perpendicular} = \frac{3}{2}$

Multiply $- - \frac{3}{2}$ .

Multiply $- 1$ by $- 1$ .

$m_{perpendicular} = 1 (\frac{3}{2})$

Multiply $\frac{3}{2}$ by $1$ .

$m_{perpendicular} = \frac{3}{2}$

Step 6

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $\frac{3}{2}$ and a given point $(0, 0)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (0) = \frac{3}{2} \cdot (x - (0))$

Simplify the equation and keep it in point-slope form.

$y + 0 = \frac{3}{2} \cdot (x + 0)$

Step 7

Write in $y = m x + b$ form.

Solve for $y$ .

Add $y$ and $0$ .

$y = \frac{3}{2} \cdot (x + 0)$

Simplify $\frac{3}{2} \cdot (x + 0)$ .

Add $x$ and $0$ .

$y = \frac{3}{2} \cdot x$

Combine $\frac{3}{2}$ and $x$ .

$y = \frac{3 x}{2}$

Reorder terms.

$y = \frac{3}{2} x$

Step 8

Find Any Equation Perpendicular to the Line 2x+3y=-17

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